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Frequently Asked Questions...

PHYSICS QUESTION PLEASE HELP! -- A flight attendant pulls her 70.0 N flight bag a distance of 253 m along a...?

...level airport floor at a constant velocity. The force she exerts is 40.0 N at an angle of 52.0 degrees above the horizontal. Find the following:

1. the work she does on the flight bag
2. the work done by the force of friction on the flight bag
3. the coefficient of kinetic friction between the flight bag and the floor

THANK YOU FOR YOUR HELP!!!!


Best Answer...

Answer:

Try this:

a) W=(F cos 0)s where F is the force she exerts, 0 is the angle the force makes with the ground, and s is the displacement:
W=(40 (cos 52))253 = -1649.5 if that doesn't work try +1649.5

b)W(nonconservative)=.5(m)(v)(v) - (v)(v) means v squared- and W=.5mv(v) so 1649=.59(686)v(v) so v = 2.19 and Friction=.59(686)(2.14)(2.14) so Friction = 1570 N

c)Ff=Mew(Fn) Mew is the Greek symbol for coefficient of kinetic friction
1570=Mew(1649.5) solve for Mew

I don't know if these are right or not


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